Question

[van ngu nhu nam xua]

soa sanh A=2004-2003/2003+2004  với B=2004^-2003^2/2004^2+2003^2

Answer 1

[Nguyễn Thị Thương Hoài]

A = \(\dfrac{2004-2003}{2003+2004}\) = \(\dfrac{\left(2004-2003\right).\left(2004+2003\right)}{\left(2003+2004\right).\left(2004+2003\right)}\) =\(\dfrac{2004^2-2003^2}{\left(2003+2004\right)^2}\)

Vì 2003² + 2004² < (2003 + 2004)²

Nên A < B