Question

[Bùi Thái Sang]

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\(\left(1-m^2\right)x=m^2-m\)

\(\Leftrightarrow\left(1-m\right)\left(1+m\right)x=m\left(m-1\right)\)

\(\Leftrightarrow x=\frac{m\left(m-1\right)}{\left(1-m\right)\left(1+m\right)}\)

\(\Leftrightarrow x=\frac{-m\left(1-m\right)}{\left(1-m\right)\left(1+m\right)}\)

Answer 1

[Vũ Nguyễn Nam Khánh]

7 not.chuc ban hoc tot.