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Bài 1: Ta có: \(4\dfrac{3}{5}+\dfrac{7}{10}< X< \dfrac{20}{3}\)
\(\dfrac{23}{5}+\dfrac{7}{10}< X< \dfrac{20}{3}\)
\(\dfrac{138}{30}< X< \dfrac{200}{3}\)
\(\Rightarrow X\in\left\{\dfrac{160}{30};\dfrac{161}{30};\dfrac{162}{30};...;\dfrac{198}{30};\dfrac{199}{30}\right\}\)
Bài 2: \(X-2019\dfrac{2}{13}=3\dfrac{7}{26}+4\dfrac{7}{52}\)
\(\Rightarrow X-\dfrac{26249}{13}=\dfrac{85}{26}+\dfrac{215}{52}\)
\(\Rightarrow X-\dfrac{26249}{13}=\dfrac{385}{52}\)
\(\Rightarrow X=\dfrac{105381}{52}\)
`4/11<x/20<5/11`
`=>80/220<11x/220<100/220`
`=>80<11x<100`
`=> x=8` hoặc `x=9`
`a, 2/3 +3/4 = (8+9)/12=17/12.`
`1 1/3+4/5 = 4/3 + 4/5 = (20+12)/15=32/15`.
`=> x=2.`
`b, 5/6-1/4=(20-6)/24=7/12`.
`2 1/3-2/5= 7/3-2/5 = (35-6)/15=29/15`.
`=> x=1`.
a) \(\dfrac{1}{10}=0,1\)
\(\dfrac{1}{100}=0,01\)
\(\dfrac{1}{1000}=0,001\)
\(\dfrac{1}{10000}=0,0001\)
b) \(\dfrac{84}{10}=8,4\)
\(\dfrac{225}{100}=2,25\)
\(\dfrac{6453}{100}=64,53\)
\(\dfrac{25789}{10000}=2,5789\)
\(\overline{36,75x4}\) < \(\dfrac{367544}{10000}\)
\(\overline{36,75x4}\) < 36,7544
vì 36,7504 < 36,7514< 36,7524< 36,7534< 36,7544
\(x\) = 0; 1; 2; 3
b, \(\overline{ab5,728}\) < \(\overline{ab5,7x4}\) < \(\overline{ab5,755}\)
vì \(\overline{ab5,728}\) < \(\overline{ab5,734}\) < \(\overline{ab5,744}\) < \(\overline{ab5,754}\) < \(\overline{ab5,755}\)
vậy \(x\) = 3; 4; 5