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\(\dfrac{3}{4}+\dfrac{1}{4}:x=2\)

=>\(\dfrac{1}{4}:x=2-\dfrac{3}{4}=\dfrac{5}{4}\)

=>\(x=\dfrac{1}{4}:\dfrac{5}{4}=\dfrac{1}{5}\)

17 tháng 5

\(\dfrac{3}{4}+\dfrac{1}{4}:x=2\)

\(=>\dfrac{1}{4}:x=2-\dfrac{3}{4}=\dfrac{8}{4}-\dfrac{3}{4}\)

\(=>\dfrac{1}{4}:x=\dfrac{5}{4}\)

\(=>x=\dfrac{1}{4}:\dfrac{5}{4}=\dfrac{1}{4}\times\dfrac{4}{5}\)

\(=>x=\dfrac{1}{5}\)

Vậy...

`#Hoshiii`

20 tháng 1 2022

x= 3/20

20 tháng 1 2022

4/30

13 tháng 7 2023

uh là nhân

14 tháng 7 2023

a) \(=\dfrac{254x\left(400-1\right)-145}{254+\left(400-1\right)x253}=\dfrac{254x400-254-145}{254+253x400-253}\)

\(=\dfrac{101600-399}{101200+1}=\dfrac{101211}{101201}=\dfrac{101201+10}{101201}=1+\dfrac{10}{101201}\)

b) \(=\dfrac{5392+\left(600+1\right)x5391}{5392x\left(600+1\right)-69}=\dfrac{5392+600x5391+5391}{5392x600+5392-69}\)

\(=\dfrac{10783+3234600}{3235200+5323}=\dfrac{\text{3245383}}{\text{3240523}}=\dfrac{3240523+60}{3240523}=1+\dfrac{60}{3240523}\)

c) \(=\dfrac{1}{2}x\left(\dfrac{1}{2}-\dfrac{1}{4}\right)+\dfrac{1}{2}x\left(\dfrac{1}{4}-\dfrac{1}{8}\right)+\dfrac{1}{32}\)

\(=\dfrac{1}{2}x\left(\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{8}\right)+\dfrac{1}{32}\)

\(=\dfrac{1}{2}x\left(\dfrac{1}{2}-\dfrac{1}{8}\right)+\dfrac{1}{32}=\dfrac{3}{16}+\dfrac{1}{32}=\dfrac{7}{32}\)

D
datcoder
Giáo viên
21 tháng 9 2023

a) \(\dfrac{2}{3}+\dfrac{3}{4}< x< 1\dfrac{1}{3}+\dfrac{4}{5}\)

\(\dfrac{2\times4}{3\times4}+\dfrac{3\times3}{4\times3}< x< \dfrac{\left(1\times3+1\right)\times5}{3\times5}+\dfrac{4\times3}{5\times3}\)

\(\dfrac{8}{12}+\dfrac{9}{12}< x< \dfrac{20}{15}+\dfrac{12}{15}\\ \dfrac{17}{12}< x< \dfrac{32}{15}\)

Ước tính: \(\dfrac{17}{12}=1,4\) và \(\dfrac{32}{15}=2,1\). Vậy số tự nhiên x = 2 sẽ thõa mãn 1,4 < x < 2,1

b)

 \(\dfrac{5}{6}-\dfrac{1}{4}< x< 2\dfrac{1}{3}-\dfrac{2}{5}\\ \dfrac{5\times4}{6\times4}-\dfrac{1\times6}{4\times6}< x< \dfrac{\left(2\times3+1\right)\times5}{3\times5}-\dfrac{2\times3}{5\times3}\\ \dfrac{20}{24}-\dfrac{6}{24}< x< \dfrac{35}{15}-\dfrac{6}{15}\\ \dfrac{14}{24}< x< \dfrac{29}{15}\)

Ước tính \(\dfrac{14}{24}=0,5\) và \(\dfrac{29}{15}=1,9\)

Vậy với x là số tự nhiên x = 1 sẽ thõa mãn 0,5 < x < 1,9

21 tháng 9 2023

1,4 là sao mik chưa học ,

20 tháng 11 2021

a)=2

b)=1/3

22 tháng 4 2023

\(x:3\dfrac{1}{15}\) - \(\dfrac{3}{4}\) = 2\(\dfrac{1}{4}\)

\(x\)\(\dfrac{46}{15}\) - \(\dfrac{3}{4}\) = \(\dfrac{9}{4}\)

\(x\) : \(\dfrac{46}{15}\)      = \(\dfrac{9}{4}\) + \(\dfrac{3}{4}\)

\(x\) : \(\dfrac{46}{15}\)     = \(\dfrac{12}{4}\)

\(x\) : \(\dfrac{46}{15}\)     = \(3\)

\(x\)              = 3 \(\times\) \(\dfrac{46}{15}\)

\(x\)             = \(\dfrac{46}{5}\)

22 tháng 4 2023

\(x\) \(\times\) 3\(\dfrac{2}{3}\) - 1\(\dfrac{2}{3}\) = 2\(\dfrac{1}{3}\)

\(x\) \(\times\) \(\dfrac{11}{3}\) - \(\dfrac{5}{3}\) = \(\dfrac{7}{3}\)

\(x\) \(\times\) \(\dfrac{11}{3}\) = \(\dfrac{7}{3}\) + \(\dfrac{5}{3}\)

\(x\) \(\times\) \(\dfrac{11}{3}\) = \(\dfrac{12}{3}\)

\(x\times\dfrac{11}{3}\) = 4

\(x\)          = 4 : \(\dfrac{11}{3}\)

\(x\)         = \(\dfrac{12}{11}\)

18 tháng 8 2023

     C =           \(\dfrac{1}{2}\) + \(\dfrac{1}{4}\) + \(\dfrac{1}{8}\) + \(\dfrac{1}{16}\) + \(\dfrac{1}{32}\) + \(\dfrac{1}{64}\) + \(\dfrac{1}{128}\)

  2\(\times\)C =   1 +  \(\dfrac{1}{2}\)  + \(\dfrac{1}{4}\) + \(\dfrac{1}{8}\) + \(\dfrac{1}{16}\) + \(\dfrac{1}{32}\) + \(\dfrac{1}{64}\) 

\(\times\) C - C =   1 -  \(\dfrac{1}{128}\)

       C       = \(\dfrac{127}{128}\)

 

6 tháng 7 2023

\(\dfrac{1}{3}+\dfrac{5}{6}\cdot\left(x-\dfrac{11}{5}\right)=\dfrac{3}{4}\)

\(\dfrac{5}{6}\cdot\left(x-\dfrac{11}{5}\right)=\dfrac{3}{4}-\dfrac{1}{3}\)

\(\dfrac{5}{6}\cdot\left(x-\dfrac{11}{5}\right)=\dfrac{5}{12}\)

\(x-\dfrac{11}{5}=\dfrac{5}{12}\cdot\dfrac{6}{5}\)

\(x-\dfrac{11}{5}=\dfrac{1}{2}\)

\(x=\dfrac{1}{2}+\dfrac{11}{5}\)

\(x=\dfrac{27}{10}\)

\(\dfrac{5}{6}\left(x-\dfrac{11}{5}\right)=\dfrac{3}{4}-\dfrac{1}{3}\)

\(\dfrac{5}{6}\left(x-\dfrac{11}{5}\right)=\dfrac{5}{12}\)

\(x-\dfrac{11}{5}=\dfrac{5}{12}:\dfrac{5}{6}\)

\(x-\dfrac{11}{5}=\dfrac{1}{2}\)

\(x=\dfrac{1}{2}+\dfrac{11}{5}=\dfrac{27}{10}\)

6 tháng 11 2021

\(\Rightarrow x+\dfrac{1}{6}=\dfrac{3}{4}\\ \Rightarrow x=\dfrac{7}{12}\)

31 tháng 7 2023

\(2\dfrac{3}{4}=\dfrac{2\times4+3}{4}=\dfrac{11}{4}\\ 3\dfrac{4}{5}=\dfrac{3\times5+4}{5}=\dfrac{19}{5}\\ 4\dfrac{3}{5}=\dfrac{4\times5+3}{5}=\dfrac{23}{5}\\ 11\dfrac{12}{13}=\dfrac{11\times13+12}{13}=\dfrac{155}{13}\\ 12\dfrac{11}{13}=\dfrac{12\times13+11}{13}=\dfrac{167}{13}\\ 3\dfrac{3}{5}=\dfrac{3\times5+3}{5}=\dfrac{18}{5}\)

31 tháng 7 2023

2\(\dfrac{3}{4}\)=\(\dfrac{11}{4}\)

3\(\dfrac{4}{5}\)=\(\dfrac{19}{5}\)

4\(\dfrac{3}{5}\)=\(\dfrac{23}{5}\)

11\(\dfrac{12}{13}\)=\(\dfrac{155}{13}\)

12\(\dfrac{11}{13}\)=\(\dfrac{167}{13}\)

3\(\dfrac{3}{5}\)=\(\dfrac{18}{5}\).

5 tháng 6 2023

\(3\dfrac{1}{2}+4\dfrac{5}{7}-5\dfrac{5}{14}\)

\(\dfrac{7}{2}+\dfrac{33}{7}-\dfrac{75}{14}\)

\(\dfrac{49}{14}+\dfrac{66}{14}-\dfrac{75}{14}\)

\(\dfrac{40}{14}=\dfrac{20}{7}\)

\(4\dfrac{1}{2}+\dfrac{1}{2}\div5\dfrac{1}{2}\)

=\(\dfrac{9}{2}+\dfrac{1}{2}\div\dfrac{11}{2}\)

=\(\dfrac{9}{2}+\dfrac{1}{2}\times\dfrac{2}{11}\)

=\(\dfrac{9}{2}+\dfrac{1}{11}\)

=\(\dfrac{101}{22}\)

\(x\times3\dfrac{1}{3}=3\dfrac{1}{3}\div4\dfrac{1}{4}\)

\(x\times\dfrac{10}{3}=\dfrac{10}{3}\div\dfrac{17}{4}\)

\(x\times\dfrac{10}{3}=\dfrac{10}{3}\times\dfrac{4}{17}\)

\(x\times\dfrac{10}{3}=\dfrac{40}{51}\)

\(x=\dfrac{40}{51}\div\dfrac{10}{3}\)

\(x=\dfrac{40}{51}\times\dfrac{3}{10}\)

\(x=\dfrac{120}{510}=\dfrac{12}{51}=\dfrac{4}{7}\)

\(5\dfrac{2}{3}\div x=3\dfrac{2}{3}-2\dfrac{1}{2}\)

\(\dfrac{17}{3}\div x=\dfrac{11}{3}-\dfrac{5}{2}\)

\(\dfrac{17}{3}\div x=\dfrac{7}{6}\)

\(x=\dfrac{17}{3}\div\dfrac{7}{6}\)

\(x=\dfrac{17}{3}\times\dfrac{6}{7}\)

\(x=\dfrac{102}{21}=\dfrac{34}{7}\)